Find \(x\)
\begin{align}3^2+4^2 & = x^2\\
\sqrt{25} & =x\\
So \quad x & =5
\end{align}
\begin{align}x^2+8^2 & = 10^2\\
x^2 & =100-64\\
x & =\sqrt{36}\\
So \quad x & =6
\end{align}
\begin{align}10.5^2+x^2 & = 17.5^2\\
x^2 & = 17.5^2-10.5^2\\
x & = \sqrt{196} \\
So \quad x & =14
\end{align}
\begin{align}\\(9\sqrt{2})^2+(12\sqrt{2})^2 & = x^2\\
x^2 & =162+288\\
x & = \sqrt{450}\\
So \quad x & =15\sqrt{2}
\end{align}