Find \(x\)

1 x
\begin{align}1^2+1^2 & = x^2\\ 2 & = x^2\\ So \quad x & = \sqrt{2} \end{align}
x 6
\begin{align}6^2+6^2 & = x^2\\ 72 & = x^2\\ x & =\sqrt{72}\\ So \quad x & =6\sqrt{2} \end{align}
x √32
\begin{align}(\sqrt{32})^2+(\sqrt{32})^2 & = x^2\\ x^2 & = 64\\ x & = \sqrt{64} \\ So \quad x & =8 \end{align}
x 1.2
\begin{align}1.2^2+1.2^2 & = x^2\\ x^2 & =2.88\\ x & = \sqrt{2.88}\\ So \quad x & =\frac{6\sqrt{2}}{5} \end{align}