Given that

g (x) = 3 x^{2}

and

h (x) = x - 2,

evaluate:

$g h (1)$

\begin{aligned} g (1 - 2) & = g (- 1) \\ = 3 (- 1)^{2} \\ = 3 \end{aligned}

$h g (3)$

\begin{aligned} h (3 (3)^{2}) & = h (27) \\ = 27 - 2 \\ = 25 \end{aligned}

$g h (3)$

\begin{aligned} g (3 - 2) & = g (1) \\ = 3 (1)^{2} \\ = 3 \end{aligned}

$g g (- 2)$

\begin{aligned} g (3 (- 2)^{2}) & = g (12) \\ = 3 (12)^{2} \\ = 432 \end{aligned}